Question

Two particles undergo SHM along parallel lines with the same time period (T) and equal amplitudes, At a particular instant, one particle is at its extreme position while the other is at its mean position. They move in the same direction. They will cross each other after a further time



(1) T/8 (2) 3T/8 (3) T/6 (4) 4T/3

Answer 1

Let one be at 0 and other be at A . its clear that they will meet at
$\frac{a}{2}$
and u can find the time taken easily

Answer 2

Answer:

3 T / 8

Explanation:

x = A sin ( wt – pi/2)  

therefore ,  sin ( wt – pi/2) = sin wt

therefore ,  2 wt – pi/2 = pi

therefore , 2 wt = 3/2 pi

wt = 3 pi/4

therefore , t = 3 pi/ 4w

therefore , t = 2 pi/w ( 3/8 )

t = 3 T /8