Two particles undergo shm along parallel lines with the same time period (t) and equal amplitudes, at a particular instant, one particle is at its extreme position while the other is at its mean position. They move in the same direction. They will cross each other after a further time
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They will cross each other after time, t
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Answer:
3 T / 8
Explanation:
x = A sin ( wt – pi/2)
therefore , sin ( wt – pi/2) = sin wt
therefore , 2 wt – pi/2 = pi
therefore , 2 wt = 3/2 pi
wt = 3 pi/4
therefore , t = 3 pi/ 4w
therefore , t = 2 pi/w ( 3/8 )
t = 3 T /8
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