two perpendicular forces of magnitude 10 N and 5 N act at point. Find the resultant and angle with 10 N
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Resultant (R) = √(A² + B² + 2ABcos∅)
R = √(10² + 5² + 2 x 5 x 10 cos90
R = √( 100 + 25 + 100 x 0
R = √(125)
Tanβ = Bsin∅/ A + Bcos∅ = 5 x 1 / 10 + 5 x 0 = 5/10 = 1/2
tanβ = 1/2
R = √(10² + 5² + 2 x 5 x 10 cos90
R = √( 100 + 25 + 100 x 0
R = √(125)
Tanβ = Bsin∅/ A + Bcos∅ = 5 x 1 / 10 + 5 x 0 = 5/10 = 1/2
tanβ = 1/2
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