Question

two perpendicular forces of magnitude 10 Newton and 5 Newton act as a point. find their resultant​

Answer 1

THE ANSWER IS AS SHOW IN THE ABOVE PICTURE

Answer 2

» Two perpendicular forces of magnitude 10 N and 5 N act as a point.

Here..

A = 10 N and B = 5 N

Both A and B act perpendicular to each other. Means the angle between them is 90°.

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• We have to find their resultant (R).

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According to Traingle's Law.

$R \: = \: \sqrt{ {A}^{2} \: + \: {B}^{2} \: + \: 2AB \: cos \theta }$

=> $R \: = \: \sqrt{ {(10)}^{2} \: + \: {(5)}^{2} \: + \: 2(10)(5) \: cos \:90° }$

=> $R \: = \: \sqrt{ 100 \: + \: 25\: + \: 100 \: cos \:90°}$

We know that..

cos 90° = 0

=> $R \: = \: \sqrt{ 100 \: + \: 25\: + \: 100 (0)}$

=> $R \: = \: \sqrt{ 125}$

=> $R\:=\:5\sqrt{5}\:N$

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Resultant (R) = 5√5 N

__________ [ANSWER]

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