Two persinson the same side of a tall buildings notice the angle of elevation of the top of the building be 30° and 60° respectively if the height of building is 72m,find the distance between the two persons.(✓3=1.73)
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P=72m.
B1=?
Angle A = 30
Tan30=P/B
1/√3=72/B1
B1= 72*1.73
B1=124.56m.
B2=?
Angle B= 60
Tan60=P/B
√3=72/B2
B2=72/1.73
B2=41.62
Distance between two boys = B1+B2
=124.56+41.62
B. =166.18m.
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