Question

two person a and b are initially at point p on a circular path of radius 3.5m . person a start moving on circular path with constant speed 5.5m/s at t=0 sec . person b initially at rest starts moving diametrically with constant acceleration at t=1 sec . the maximum acceleration of person B so that he meets person A at point Q on circular path is

Answer 1

B will meet at diametrically apposite end so,
Distance travelled by A
= half the perimeter
=2πr/2
=πr
=[22/7] x 3.5
=11 m

Time taken by the person A to cover this distance 
time =distance/speed
time=11/5.5=2s

Now B starts his journey at t= 1s that means 1 second has already passed.
So, B has only 1 sec to cover the diameter distance.
by using equation of motion
S=ut+[1/2]at²
11=[0*t]+[1/2]a[1²]
a=22m/s²

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Answer 2

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