Two persons are holding a rope of negligible weight tightly at its ends so that it is horizontal. A 15 kg
weight is attached to the rope at the mid point which now no longer remains horizontal. The
minimum tension required to completely straighten the rope is:
15
(A) 15 kg
(B) -kg
2
(C) 5 kg
(D) Infinitely large (or not possible)
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Answer:
ANSWER
The tension required to bring the string into horizontal position can be found out using the
following formulae.
2Tsinx=mg
The following equation is true for body which attains equilibrium. Also, when the body will
be in equilibrium the angle formed will be 0.
Therefore,
T=mg/2sinx, where x=0
T=mg/2sin0, where the value of sin=0
Then, the amount of tension required is infinite.
Explanation:
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