Question

Two persons are holding a rope of negligible weight tightly at its ends so that it is horizontal. A 15 kg
weight is attached to the rope at the mid point which now no longer remains horizontal. The
minimum tension required to completely straighten the rope is:
15
(A) 15 kg
(B) -kg
2
(C) 5 kg
(D) Infinitely large (or not possible)
actively
F​

Answer 1

Answer:

ANSWER

The tension required to bring the string into horizontal position can be found out using the

following formulae.

2Tsinx=mg

The following equation is true for body which attains equilibrium. Also, when the body will

be in equilibrium the angle formed will be 0.

Therefore,

T=mg/2sinx, where x=0

T=mg/2sin0, where the value of sin=0

Then, the amount of tension required is infinite.

Explanation:

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