Question

Two persons just manage to push a block from left to right direction along a horizontal level road with uniform velocity. When the same block is pushed by three persons in same direction a constant acceleration of 0.2 ms–2 is produced in the block. If the five persons push the block in same direction together, then the magnitude of acceleration of the block will be [Assume that each person applies the force equal in magnitude]

Answer 1

When 2 person pulls the box it will move to the right with constant speed

So applied force = friction force

F_f = 2FFf​=2F

When 3 person apply force on it

3F - F_f = ma3F−Ff​=ma

3F - 2F = 0.2m3F−2F=0.2m

Now when 5 person apply the same force then we have

5F - F_f = ma5F−Ff​=ma

5F - 2F = ma5F−2F=ma

3F = ma3F=ma

from above equation F = 0.2m

3*0.2m = ma3∗0.2m=ma

a = 0.6 m/s^2a=0.6m/s2

so acceleration will be 0.6 m/s^2

Answer 2

Answer:

0.2 metre per second sq

Explanation: