Question

two persons on the sane side of a tall building notice the angle of elevation of the top of the building to be 30° and 60° respectively. lf the height of the building is 72m, find the distance between the two persons.(√3=1.73)

Answer 1

Answer:

let the height of building(AB) and distance from buildings are x(C) and y(D) meter.

then in triangle ABC ,

tan 30° = AB/BC

⇒√3 =72/x

⇒x= 72/√3

⇒x=24√3

again in triangle ABD

tan 60 °= AB/BD

⇒1/√3=72/y

⇒y= 72√3

then total distance

BD= x+y

BD=24√3+72√3

⇒BD=96√3

⇒BD= 166.08 m