two persons on the side of a tall building notice the angle of elevation on the top of the building to be 30 degree and 60 degree respectively if the height of the building is 72 find the distance between the two persons
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Hey Brainly
Here u go
A------------------------------B----------------------C
x y
let CD is the building and A & B are the two person. join the point A with D and B with D. from A elevation is 30 degree and from B elevation is 60 degree.
AB = distance between two person = x m
in triangle ACD
tan 30 = CD/AC
1/√3 = 60/AC
AC = 60√3
x+y = 60√3 -----------------(1)
in triangle BCD
tan 60 = CD/BC
√3 = 60/BC
BC = 60/√3
y = 60/√3
put the value of y in equation (1)
x + 60/√3 = 60√3
x = 60√3 - 60/√3
x = 60(3-1)/√3
x = 120/√3
x = 40√3 meter
Here u go
A------------------------------B----------------------C
x y
let CD is the building and A & B are the two person. join the point A with D and B with D. from A elevation is 30 degree and from B elevation is 60 degree.
AB = distance between two person = x m
in triangle ACD
tan 30 = CD/AC
1/√3 = 60/AC
AC = 60√3
x+y = 60√3 -----------------(1)
in triangle BCD
tan 60 = CD/BC
√3 = 60/BC
BC = 60/√3
y = 60/√3
put the value of y in equation (1)
x + 60/√3 = 60√3
x = 60√3 - 60/√3
x = 60(3-1)/√3
x = 120/√3
x = 40√3 meter
mrjd6:
it's really helped me
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2
Hope this helps and please don't mind the handwriting.
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