Two phasor A and B are given as A = 3+j1 and B = 4+j3. Calculate the values of
a) A + B
b) A - B
C) AB
d) A/B
Express the results in both polar and rectangular co-ordinates.
Answers
Answered by
1
Answer:
A+b+11-11ab11 7upon 4
Answered by
5
Answer:
given = A = 3+j1
B = 4+j3
to find = a) A + B
b) A - B
C) AB
d) A/B
Express the results in both polar and rectangular co-ordinates.
solution :-
A +B = (3 + j ) + (4 + 3j ) = 7 + 4j
A - B = (3 - j ) - (4 + 3j ) = -1-4j
AB = ( 3 +i ) (4 + 3j ) = 12 - 3 + j(13)
AB = 9+13j
A / B = 15 - 5j /25 = 3/ 5 - 1/5 j
and polar form
m = tanθ tan⁻¹ (y/ n )
θ = tan⁻¹ (-1/3)
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