Question

two pieces of length 2 3/5m and 3 3/10 are4 cut off from a rope 11 mlong.what is the length the remaining rope

Answer 1

Length of the first piece = 2 3/5 m=13/5 m
Length of the second piece= 3 3/10 m= 33/10 m
Total length of the rope= 11 m
LCM of 5 and 10 = 10
13/5 * 2/2 = 26/10 m
Remaining length= 11-(26/10+33/10)
                            = 11-59/10
11/1*10/10= 110/10
                            = 110/10-59/10
                            = 51/10 m
                            = 5.1 m