Question

two pieces of lengths 2(3/5)m and 3(3/10)m are cut off from a rope 11m long .what is the remaining length of rope

Answer 1

2(3/5)=13/5    ,3(3/10)=33/10
11-13/5+33/10 
11-59/10
110-59/10
51/10
5.1m

Answer 2

$remaining=11-(2\frac{3}{5}+3\frac{3}{10}) \\ remaining=11-(2.6+1.3) \\ remaining=11-(3.9) \\ remaining=7.1$

The remaining length is 7.1m