Two pieces of metals are suspended from the arms of a
balance and are found to be in equilibrium when kept
immersed in water. The mass of one piece is 32 g and its
density 8 g cm⁻³. The density of the other is 5 g per cm³.
Then the mass of the other is
(a) 28 g (b) 35 g (c) 21 g (d) 33.6 g
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Explanation:
Volume of first piece of metal =
8
32
=4cm
2
Upthrust = 4 gf
Effective weight = (32 -4) gf = 28 gf
If m be the mass of second body, volume of second body
5
m
Now, 28 = m -
5
m
⇒m = 35 g
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