Physics, asked by marwansnoopy7635, 10 months ago

Two pieces of metals are suspended from the arms of a
balance and are found to be in equilibrium when kept
immersed in water. The mass of one piece is 32 g and its
density 8 g cm⁻³. The density of the other is 5 g per cm³.
Then the mass of the other is
(a) 28 g (b) 35 g (c) 21 g (d) 33.6 g

Answers

Answered by vinaydalal9708
0

Explanation:

Volume of first piece of metal =

8

32

=4cm

2

Upthrust = 4 gf

Effective weight = (32 -4) gf = 28 gf

If m be the mass of second body, volume of second body

5

m

Now, 28 = m -

5

m

⇒m = 35 g

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