Question

two pillars ab and CD are 50 metres apart and the height of the pillar CD is double the height of pillar ab from a point P on the line joining the feet of the Pillar and observer observes the top a of the pillar a b and a Topsy of the Taylor series at angles of elevation 30° and 60° respectively find the height of the pillar ab and CD

Answer 1

Answer:

it is easy questions

Step-by-step explanation:

i will guide so first find third side by pythogores therom then calculate angle

after u get a answer

find the height

Answer 2

The height of pillar AB is $10\sqrt{3}\ m$

The height of pillar CD is $20\sqrt{3}\ m$

Step-by-step explanation:

Two pillars AB and CD are 50 m apart.

Let the height of pillar AB be h m

The height of the pillar CD is double the height of pillar AB

Height of pillar CD  = 2h

From a point P on the line joining the feet of the Pillar (BD)  and observer observes the top a of the pillar AB and a top of the pillar CD at angles of elevation 30° and 60° respectively

Please find attachment for figure.

In ΔABP, ∠ABP = 90°

$\tan30^\circ=\dfrac{AB}{BP}$

$BP=h\cot30^\circ$

In ΔCDP, ∠CDP = 90°

$\tan60^\circ=\dfrac{CD}{DP}$

$DP=2h\cot60^\circ$

As we know,

BP + DP = 50

$h\cot30^\circ+2h\cot60^\circ=50$

$h=\dfrac{50}{\cot30^\circ+2\cot60^\circ}$

$h=10\sqrt{3}\ m$

The height of pillar AB is $10\sqrt{3}\ m$

The height of pillar CD is $20\sqrt{3}\ m$

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