two pillars each of cross sectional area 10cm^2 support a load of 40kg mass. calculate the pressure sustained by the pillar.
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Answered by
7
solution______
A= 10 cm^2,
L= 40kg
P= F/A ; F= mg => 4×10= 400kg
P = 400/ 20×10^-4
= 240 × 10^14
= 2 × 10^5 N/m^2.
___________
A= 10 cm^2,
L= 40kg
P= F/A ; F= mg => 4×10= 400kg
P = 400/ 20×10^-4
= 240 × 10^14
= 2 × 10^5 N/m^2.
___________
Answered by
4
10 cm2 =0.001 m2
total area = 0.002 m2
pressure=force/area
force=mass * acc.
f=40*10 (taking g as 10 m/s2)
p=400/0.002
p=200000 pa
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