two pipe a and b can fill a tank in 18 minutes and 24 minutes respectively if both the pipes are opened simultaneously theh after how much time should pipe B be closed so that the tank is full in 12 minutes
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Step-by-step explanation:
Pipe A is open for 18 min. So, 18 * 4 = 72 units of tank will get filled. Remaining (96-72) =24 units will be filled by pipe B. Time taken by pipe B to fill 24 units = 24/3 = 8 min.
or
Let the total capacity of the tank be 96 units (LCM of 24 & 32).
A fills = 96/24 = 4 units / minute.
B fills = 96/32 = 3 units / minute.
Let the time for which B is opened is x minutes.
According to the question, 4 × 18 + 3 × x = 96
3x = 96 - 72 = ⇒ 3x = 24
x = 8 minutes.
The pipe B should be closed after 8 minutes.
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