Question

Two pipes a and b are fitted with a tank .Pipe a can fill 3/5th of the tank in 27 hours while pipe b can fill the empty tank completely in 30 hours in what time will the both pipes together fill the empty tank completely

Answer 1

3/5 in27 hr so total it takes 45 hr. let it be A

b take 30 hrs

lcm (45,30)= 90

a=2 b=3

this is the efficiency

both together means 5 efficency

90/5=18 hr

Answer 2

Both the pipes takes 90 hours to empty the tank completely.

Step-by-step explanation:

Since we have given that

Number of hours taken by A to fill the tank is given by

$27\div \dfrac{3}{5}\\\\=27\times \dfrac{5}{3}\\\\=9\times 5\\\\=45$

Number of hours taken by B to empty the tank = 30 hours

So, Altogether they need to fill the tank completely.

So, Lcm of 45 and 30 = 90

So, Work done by A = $\dfrac{90}{45}=2$

Work done by B = $\dfrac{90}{30}=3$

So, Total time would be

$\dfrac{90}{2-3}=\dfrac{90}{-1}=-90\ hours$

Hence, both the pipes takes 90 hours to empty the tank completely.

# learn more:

an empty tank in 10 hour and pipe b can fill an empty tank in 12 hour. if both the pipe are open together in an empty tank, time taken to fill the empty tank

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