Question

Two point charges + 9 microcoulomb and -6 microcoulomb are placed 16 centimetre apart in air find the position of the point at which the resultant electric field is zero

Answer 1

Answer:

4.6cm from 16uC

Explanation:

+16uC____________<8r>___________-9uC

when electric field is zero; from the formula --->

q/4π€r²= q/4π€r'²

(9×10^9 ×16×10^-6)/r² =(9×10^9×9×10 ^-6)/(0.08-r)²

144/r²=81/(0.08-r)²

12/r=9/(0.08-r)

9r=0.96-12r

21r=0.98

r=4.6cm from 16uC