Two pipes A and B can fill a tank in 10 hours and 15 hours respectively.if they are opened alternately for one hour each and if A is opened first the time (in hours) required to fill the tank is.
Answers
Answer:
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Step-by-step explanation:
A:B
10:15 _30
3:2
A FILL 3 UNIT IN 1 HOUR AND B FILL 2 UNIT IN 1 HOUR
SO FIRST A OPN IT FILL 3 UNIT AND THEN B OPN IT FILL 2 UNIT
SO FIRST 2 HOUR BOTH FILL 5 UNIT
WE FILL 30 UNIT
(A+B)=2 HOURS
5=2
6×5=2×6
30 UNIT = 12 HOURS
SO IT TAKE 12 HOURS TO FILL TANK
Answer:
The tank will be filled in 12 hours if both the taps are open alternatively.
Step-by-step explanation:
In 10 hours, pipe A fill a tank
In 1 hour, pipe A fill 1/10 of tank
In 15 hours, pipe B fill a tank
In 1 hour, pipe B fill 1/15 of tank
A's 1 hour work + B's 1 hour work
=> 1/10 + 1/15 = 3+2/30 = 5/30 = 1/6
Hence, if both the taps are opened alternatively, then the tank will be filled in 6×2 = 12 hours.
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