Math, asked by hatkarthukaram1996, 10 months ago

Two pipes A and B can fill a tank in 10 hours and 15 hours respectively.if they are opened alternately for one hour each and if A is opened first the time (in hours) required to fill the tank is.

Answers

Answered by guptarajat698
1

Answer:

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Step-by-step explanation:

A:B

10:15 _30

3:2

A FILL 3 UNIT IN 1 HOUR AND B FILL 2 UNIT IN 1 HOUR

SO FIRST A OPN IT FILL 3 UNIT AND THEN B OPN IT FILL 2 UNIT

SO FIRST 2 HOUR BOTH FILL 5 UNIT

WE FILL 30 UNIT

(A+B)=2 HOURS

5=2

6×5=2×6

30 UNIT = 12 HOURS

SO IT TAKE 12 HOURS TO FILL TANK

Answered by SidhantVerma77
0

Answer:

The tank will be filled in 12 hours if both the taps are open alternatively.

Step-by-step explanation:

In 10 hours, pipe A fill a tank

In 1 hour, pipe A fill 1/10 of tank

In 15 hours, pipe B fill a tank

In 1 hour, pipe B fill 1/15 of tank

A's 1 hour work + B's 1 hour work

=> 1/10 + 1/15 = 3+2/30 = 5/30 = 1/6

Hence, if both the taps are opened alternatively, then the tank will be filled in 6×2 = 12 hours.

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