Question

two pipes A and B can fill a tank in 10 minutes and 15 minutes respectively and another pipe C can empty it in 12 minutes. lf these pipes are opened alternatively for 1 minutes each. Beginning with first, in how much time will the tank be full?​

Answer 1

Answer:

Step-by-step explanation:

A can fill the whole tank in 10min.

In 1min it can fill 1/10part.

B can fill the whole tank in 15min.

In 1min it can fill 1/15part.

C can empty the whole tank in 12min.

In 1min it can fill -1/12part.

Since they are kept open for 1min each.

So, in 3min they fill = 1/10+1/15+(-1/12)

= 1/10+1/15-1/12

= 5/60= 1/12

Now, let in x intervals of 3min the whole tank is filled.

1/12+1/12+1/12....=1

(1/12)x=1

x= 12 intervals.

Total Time required to fill the tank = 3x12=36min