Question

find the point on the x axis which is equidistant from (2,-5) & (-2,9), with the distance formula?​

Answer 1

Answer:

(-7,0)

Step-by-step explanation:

let the points be p(x,0)

so, AP=PB and

AP^2=PB^2

(x-2)^2+(0+5)^2=(x+2^2+(0-9)^2

x^2+4-4x+25=x^2+4+4x+81

x^2+29-4x=x^2+85+4x

-4x-4x=85-29

-8x=56

x=-7

Hence, point on the x-axis which is equidistant from

(2,-5) and (-2,9) is (-7,0)