Two pipes A and B can fill a tank in 16 hours and 20 hours respectively . If both the pipes opens simultaneously , how much time it will be taken to fill the tank?
Answers
Step-by-step explanation:
Given:
Two pipes A and B can fill a tank in 16 hrs and 20 hrs
Respectively.
To find:
How much time it would take to fill the tank if both pipes are opened simultaneously.
Algorithm:
First find the water filled in 1 hr by the both pipes A and B.
Then add them together and then the result obtained
by adding them . The reciprocal of the result is your answer.
Solution:
A fills the tank in 16 hrs.
In 1 hr=1/16 .
B fills the tank in 20 hrs.
In 1 hr=1/20.
Now they are opened simultaneously;
1/16+1/20
=5+4/80=9/80
☆Now the reciprocal of 9/80 is your answer I.e 80/9=8.88888 recurring or approximately 9 hrs.
☺ Now by trick ☺:
Algorithm:
Step1.First find the LCM of time duration given for tap A and B
I.e 16 and 20 hrs.
Step 2. After finding Lcm. Divide the lcm by 16 and 20 .
Then add the quotients obtained . Thenafter divide the Lcm of 16 and 20 by result obtained from adding quotients of 16/80 and 20/80.
Solution:
Lcm of (16 ,20)=80
Now 80/16=5 And 80/20=4
Now adding 5+4=9.
Now Answer is =80/9=8.888 recurring OR 9hrs approximately.