Question

Two pipes a and b can fill a tank in 24 min and 32 min respectively. If both the pipes are opened simultaneously, after how much time b should be closed so that the tank is full in 18 minutes

Answer 1

Answer:

The answer that i have is this :

Let B be closed after x minutes Then,

part filled by(A+B) in x min + part filled by A in (18-x) min =1

thus x*(1/24+1/32) + (18-x)*1/24 = 1

7x/96+(18-x)/24 =1

7x+4(18-x)=96

x=8

Hence B is 8 min

Step-by-step explanation:

Answer 2

Answer:

after 8 min b should be close