Two pipes A and B can fill a tank in 48 min, and 64
min respectively. If both are opened simulatancously,
after how much time should B closed so that lank
filled in 36 minutes.
Answers
Answered by
0
Answer:
Hey mate here is your answer...
Step-by-step explanation:
Let the total capacity of the tank be 96 units (LCM of 24 & 32).
A fills =
24
96
= 4 units / minute.
B fills =
32
96
= 3 units / minute.
Let the time for which B is opened is x minutes.
According to the question, 4 × 18 + 3 × x = 96
3x = 96 - 72 = ⇒ 3x = 24
x = 8 minutes.
The pipe B should be closed after 8 minutes.
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