Question

two pipes a and b fill a tank in 15 and 12 hors respectively tap c empty tank in 6 hours how much rime taken to empty it

Answer 1

Answer:

ANSWER

Let the tank be emptied in x hrs after 8 A.M.

∴ Tank filled by pipe in x hours =

15

x

Tank filled by second pipe in (x - 1) hours =

12

(x−1)

Tank emptied by third pipe in (x - 3) hours =

4

(x−3)

∴

15

x

+

12

(x−1)

−

4

(x−3)

=0

⇒

60

4x+5(x−1)−15(x−3)

=0

4x+5x−5−15x+45=0⇒−6x+40=0

⇒x=

6

40

=

3

20

=6

3

2

hrs=6hrs40min

∴ The tank will be emptied at 2 : 40 p.m.

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