Question

Two pipes A and B running together can fill a tank in 3 1/3 minutes. If B pipe takes 5 more than pipe A to fill the tank separately,then find the time in which each pipe would fill the tank separately

Answer 1

Answer:

Let the time taken by pipe A =x

and by pipe B =y

ATQ

$x + y = \frac{31}{3} \\ 3x + 3y = 31 \: \: \: - - - - (1)$

x = y+5

3(x-y=5)

3x-3y =15 -----------------------------(2)

add equation (1)&(2)

3x+3y =31

+ 3x-3y =15

= 6x = 46

x =46/6

x = 7.33

time taken by A =7.33m

time taken by B = 7.33-5=2.33