two pipes can fill a tank in 12 minuets and 20minuetes respectively
Answers
Answer:
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Explanation:
It is given that two pipes can fill a tank in 12 minutes and 20 minutes respectively.
\text{Tank filled by first pipe in 1 minute}=\frac{1}{12}Tank filled by first pipe in 1 minute=
12
1
\text{Tank filled by second pipe in 1 minute}=\frac{1}{20}Tank filled by second pipe in 1 minute=
20
1
\text{Tank filled by both pipes in 1 minute}=\frac{1}{12}+\frac{1}{20}=\frac{1}{10}Tank filled by both pipes in 1 minute=
12
1
+
20
1
=
10
1
Let first pipe was open for (10-x) minutes.
\frac{1}{12}\times(10-x)+\frac{1}{20}\times10=1
12
1
×(10−x)+
20
1
×10=1
\frac{10}{12}-\frac{x}{12}+\frac{1}{2}=1
12
10
−
12
x
+
2
1
=1
\frac{16}{12}-1=\frac{x}{12}
12
16
−1=
12
x
\frac{16}{12}-1=\frac{x}{12}
12
16
−1=
12
x
\frac{4}{12}=\frac{x}{12}
12
4
=
12
x
x=4x=4