Two pipes can fill the cistern and 10 hours and 12 hours respectively while the third empty it in 20 hours if all types are opened simultaneously then the centre will be filled in
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Step-by-step explanation:
total capacity of cistern is
lcm of 10,12,20 that is 60 unit's
first pipe can fill cistern in one hour is 6 unit's
lly second pipe is 5 unit's
both 1+2=11 unit's per hour
third pipe can empty the cistern is 3 unit's per hour
all the pipes are opened simultaneously
6+5-3=8 unit's filled per hour
then total cistern filled in
60/8=7(4/8)
=7(1/2) hour s.
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