two pipes running together can fill a cistern in. 11 1/9 minutes and other takes 5 minutes more
Answers
Answer:
Step-by-step explanation:
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Answer:time taken by the faster pipe is 20mins and time taken by the slower pipe is 25mins
Step-by-step explanation:let the time taken by the faster pipe to fill the cistern be x mins
and the therefore the time taken by the slower pipe to fill the cistern is 5+x mins
let the total work done be 1
so, in 1min the faster pipe fills=1/x part of the cistern
and in 100/9 mins it fills=100/9x part of the cistern
also,in 1min the slower pipe fills=1/(x+5)part of the cistern
and in 100/9 mins it fills=100/9(x+5) part of the cistern
therefore, 100/9x + 100/9(x+5)=1
=>1/x+1/(x+5)=9/100
=>2x+5/x^2+5x=9/100
=>200x+500=9x^2+45x
=>9x^2-155x-500=0
=>9x^2-180x+25x-500=0
=>9x(x-20)+25(x-20)=0
+(x-20)(9x+25)
so,x=20 or -25/9
since time cannot be in negative , thus x=20mins
and x+5=25mins