Question

two pipes running together can fill a pipe in 11 1/9 minutes. if one pipe takes 5 mins more than the other to fill the tank separately,find the time in which each pipe would fill the tank separately.

Answer 1

11 1/9=100/9

first pipe want x m  to fill the tank
second tap want x+5 m to fill the tank

amount of water that fill through the 1st pipe in 1 miniute=$\frac{1}{x}$
"

[tex] \frac{1}{x} + \frac{1}{x+5} = \frac{100}{9} \\ \\ \frac{x+5+x}{ x^{2} +5x}= \frac{100}{9} \\ \\ 18x+45=100 x^{2} +500x \\ \\ 100 x^{2} +500x-18x=45 \\ 100 x^{2} +482x=45 \\ 100 x^{2} +482x-45=0 [/tex]
then factor it ..

Answer 2

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