Math, asked by jimborox, 1 year ago

Two pipes running together can fill a tank in 6 minutes. If one pipe takes 5 minutes more
than the other to fill the tank, find the time in which each pipe would fill the tank separately.​

Attachments:

Answers

Answered by akhil4486
2

SolutionLet the volume of cistern = V litre (L)

let the flow rate of one pipe be x L/min and that of other pipe be y L/min

Since 6 minute are needed to fill the pipe

6x+6y = V = total volume (1)

V/x = time taken by one pipe and V/y = time taken by other pipe

V/x + V/y = 5 min

1/x - 1/y = 5/V (2)

Solve

Time taken by one pipe = 15 min

and Time taken by other pipe = 10 min

Option 6) 15 min and 10 min


jimborox: can you please elaborate, it's a bit confusing
Similar questions