Two pipes running together fill a cistern in 30/11min.if one pipe takes 1min more that the other to fillthe cistern find the time in which each pipe would fill the cistern alone
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let 1st pipe take x min to fill cistern.
2nd pipe take x+1 min to fill cistern.
1/x + 1/(x+1) = 11/30
[x+1+x]/(x)(x+1) = 11/30
[2x+1]/(x^2+x) = 11/30
30[2x+1] = 11[(x^2+x)]
60x+30 = 11x^2+11x
11x^2 - 49x - 30 = 0
(11x+6)(x-5) = 0
Since x cannot be -ve, x= 5.
1st pipe 5 min
2nd pipe 6 min
2nd pipe take x+1 min to fill cistern.
1/x + 1/(x+1) = 11/30
[x+1+x]/(x)(x+1) = 11/30
[2x+1]/(x^2+x) = 11/30
30[2x+1] = 11[(x^2+x)]
60x+30 = 11x^2+11x
11x^2 - 49x - 30 = 0
(11x+6)(x-5) = 0
Since x cannot be -ve, x= 5.
1st pipe 5 min
2nd pipe 6 min
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