Physics, asked by Shoaib8900, 1 year ago

Two pith balls carrying equal charges are suspended from a common point by strings of equal length. The equilibrium separation between them is r. Now the strings are rigidly clamped at half the height. The equilibrium separation between the balls now become
(a) \bigg \lgroup \frac{r}{\sqrt[3]{2}}\bigg \rgroup
(b) \bigg \lgroup \frac{2r}{\sqrt{3}}\bigg \rgroup
(c) \bigg \lgroup \frac{2r}{3}\bigg \rgroup (d) \bigg \lgroup\frac{r}{\sqrt{2}}}\bigg \rgroup ^{2}

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Answers

Answered by choudhary21
1

Hey

The equilibrium separation between them is r.

D Correct

Answered by Dar3boy
1

Two pith balls carrying equal charges are suspended from a common point by strings of equal length. The equilibrium separation between them is r. Now the strings are rigidly clamped at half the height. The equilibrium separation between the balls now become

(a) \bigg \lgroup \frac{r}{\sqrt[3]{2}}\bigg \rgroup

(b) \bigg \lgroup \frac{2r}{\sqrt{3}}\bigg \rgroup

(c) \bigg \lgroup \frac{2r}{3}\bigg \rgroup

(d) \bigg \lgroup\frac{r}{\sqrt{2}}}\bigg \rgroup ^{2}✔️✔️

D option correct

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