two pith balls of mass M and charge Q are suspended to Silk thread of length L forum a common. If the distance between balls is X then find the value of x for equilibrium
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Answer:
(q^2×1/2πEOmg) ^1/3
Explanation:
Two identical pith balls of mass M and having charge q are suspended from a point by weightless strings of length L. If both strings make an angle of Q with the vertical and then the distance between the balls will be (taking Q to be small) :-
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