Question

Two places A & B are 300 km apart, mohit starts from city A at 8:24 am and an hour later Rohit starts from city A & after travelling for one hour he reaches at city C that mohit had passed 40 min earlier. City c falls on the way from A to B. if they reaches city B at same time. Find their speed.

Answer 1

Speed of Rohit is 100 km/h

Speed of Mohit is 75 km/h

Step-by-step explanation:

Let the speed of Mohit be x and the speed of Rohit be y

Let the distance from City A to C be d

Then,

The time taken by Rohit in reaching City C = d/y

or, d/y = 1

or, d = y

Time taken by Mohit in reaching City C = d/x

or, d/x = 1 + 1/3

or, y/x = 4/3

Time taken in reaching from City A to City B is equal but Mohit started 1 hour late

Thus,

300/x = 300/y + 1

$\implies \frac{300}{x}=\frac{300}{4x/3}+1$

$\implies 300=\frac{900}{4}+x$

$\implies 300=225+x$

$\implies x=75$ km/h

Therefore,

$y=\frac{4\times 75}{3}$

$\implies y=100$ km/h

Therefore,

Speed of Rohit is 100 km/h

Speed of Mohit is 75 km/h

Hope this helps.

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