Two planes, 2400 miles apart,fly towards each other. One flies 60 miles/hour faster. They pass after 5 hours. Find their speed.
Answers
Answered by
10
According to the Question
Two planes started 2400 miles apart
They pass each other and they must have together to cover = 2400 miles
Now
Using Formula :-
Distance = Speed × Time
First Plane ⇒ 5 × p = 5p
Second Plane ⇒ 5(p + 60)
Now put in a Equation we get :-
5p + 5(p + 60) = 2400
5p + 5p + 300 = 2400
10p + 300 = 2400
10p = 2400 - 300
10p = 2100
p = 2100 / 10
p = 210
Hence :-
One plane speed is 210 miles
Another plane speed ⇒ 210 + 60 = 270 miles
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Answered by
2
Answer:
Their speed are 210 miles/hour and 270 miles/hour respectively.
Step-by-step explanation:
Distance the both planes need to cover= 2400 miles
Distance= Speed× Time
- First plane: 5×t = 5t
- Second plane:5(p+60)
Solving the Equation:
5p+5(p+60)=2400
5p+5p+300=2400
10p+300=2400
10p= 2400-300
10p=2100
p=210
So, Speed of first plane= 210 miles/hour
Speed of second plane: 210+60= 270 miles/hour
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