Question

two planet a and b have radii r and r bi n square respectively the ratio of the time period of the revolution is

Answer 1

Answer:

don't no ,........................

Answer 2

Given :

Radius of planet A = r

and , radius of planet B = ( r / $n^{2}$ )

To find :

Ratio of the time period of the revolution of planet A and B .

Solution :

Let T$_{a}$ and T$_{b}$ be time of revolution of planet A and B .

According's to the Kepplar ' s law ,

( T$_{a}$ / T$_{b}$ ) ^ 2 = ( radius of planet A / radius of planet B ) ^ 3

                    = [ r / ( r / $n^{2}$ ) ] ^3

                    = $n^{6}$

T$_{a}$ / T$_{b}$ = ratio = $n^{3}$

Ratio of the time period of the revolution of planet A and B is  $n^{3}$ : 1