Question

two plates are placed at a distance of 0.15 mm apart . the lower plate is fixed while the upper plate having surface area 1.0 m2 is pulled at 0.3nm/s . find the force and power required to maintain this speed , if the fluid separating them is having viscosity 1.5 poise

Answer 1

Given:

Two plates are placed at a distance of 0.15 mm apart . The lower plate is fixed while the upper plate having surface area 1.0 m² is pulled at 0.3 mm/s.

To find:

Force and power required to maintain this speed.

Calculation:

Let force required be F ;

$\boxed{ \sf{F = \eta \times (area) \times \dfrac{dv}{dz} }}$

Putting all the values in SI unit ;

$\sf{ = > F = 1.5 \times (1) \times \dfrac{0.3 \times {10}^{ - 3} }{0.15 \times {10}^{ - 3} } }$

$\sf{ = > F = 1.5 \times (1) \times \dfrac{0.30 }{0.15} }$

$\sf{ = > F = 1.5 \times (1) \times 2 }$

$\boxed{ \sf{ = > F = 3 \: N }}$

Now , let power delivered be P ;

$\boxed{ \rm{ \therefore \: P = F \times v}}$

$\rm{ = > \: P = 3 \times 0.3 \times {10}^{ - 3} }$

$\rm{ = > \: P = 0.9 \times {10}^{ - 3} }$

$\boxed{\rm{ = > \: P = 9 \times {10}^{ - 4} \: watt}}$

Hope It Helps.

Answer 2

Answer:

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