Question

Two plots of land have the same perimeter. One is a square of
side 64 m and the other is a rectangle of length 70 m. Find the
breadth of the rectangular plot. Which plot has the greater area
and by how much?
5​

Answer 1

$\huge \bold{Answer:}$

⚒ Formula used:

• Perimeter of the square: 4×side
• Perimeter of the rectangle:2(length+breadth)
• Area of the square: side×side
• Area of the rectangle: Length×Breadth

⚒ Solution :

Given,

Side of the square is 64m.

Now,

Perimeter of the square= 4×64m

= 256m

Now,

Let the breadth of the rectangle be "b".

Breadth:

2(Length+Breadth)

=> 2(70+b)m = 256m

=> 140 +2b= 256

=> 2b= 256-140

=> 2b=116

=> b= 116/2

=> b= 58

Thus, The breadth of the rectangle is 58m.

Area of the square: side×side

= 64×64

= 4096m²

Area of the rectangle: length×breadth

= 70×58

= 4060m²

Area of the square-Area of the rectangle

= (4096-4060)m²

= 36m²

Therefore, The area of square is greater than area of the rectangle by 36m².