Question

Two point charges +12°C and 8°C are separated by distance of 10cm.find the work done in bringing them
4cm closer.​

Answer 1

Explanation:

Given conditions ⇒

q₁ = 12 μC = 12 × 10⁻⁶ C.

q₂ = 8 μC = 8 × 10⁻⁶ C.

Distance between them(r₁) = 10 cm. = 0.1 m.

Final Distance between them(r₂) = 6 cm . = 0.06 m.

Work done in bringing the charges upto the distance of 6 cm is given by,

W = k q₁ q₂ (1/r₂ - 1/r₁) 

= 9 × 10⁹ × 12 × 10⁻⁶ × 8 × 10⁻⁶(1/0.06 - 1/0.1)

= 864 × 10⁻³ (16.67 - 10)

= 864 × 10⁻³(6.67)

= 5760 × 10⁻³

= 5.76 J.

Hence, the work done is 5.76 J.

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