Question

Two point charges 6 µC and 2 µC are separated by 3 cm in free space. Calculate the work done in separating them to infinity.

Please give proper explanation don't copyright

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Work\:Done=-3.6\:J}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Two \: point \: charges = 6 \mu \:C \: and \: 2 \mu \: C \\ \\ \tt: \implies Separation(r) =3 \: cm \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Work \: done \: in \: separating \: them \: to \: \infty =?$

• According to given question :

$\tt \circ \: r = \frac{3}{100} = 0.03 \: m \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies Work \: Done = - \frac{k q_{1} q_{2} }{r} \\ \\ \tt \circ \: k = 9 \times {10}^{9} \\ \\ \tt: \implies Work \: Done = - \frac{9 \times {10}^{9} \times 6 \times {10}^{ - 6} \times 2 \times {10}^{ - 6} }{0.03} \\ \\ \tt: \implies Work \: Done = - \frac{9 \times 6 \times 2 \times {10}^{9 - 6 - 6} }{3 \times {10}^{ - 2} } \\ \\ \tt: \implies Work \: Done = - \frac{104 \times {10}^{ - 3 + 2} }{3} \\ \\ \tt: \implies Work \: Done = - 36 \times {10}^{ - 1} \\ \\ \green{ \tt: \implies Work \: Done = - 3.6 \: J}$