Two point charges +9e and +1e are kept at a distance of 16 cm from each other. At what point between these charges, should a third charge q to be placed so that it remains in equilibrium?
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Two charge +9e and +1e are kept at a distance of 16cm from each other , Let a q charge is kept r distance from +9e in such a way that it remains in equilibrium.
Now, at equilibrium
Force act on q due to +9e = Force act on q due to +1e
K(+9e)q/r² = k(+1e)q/(16 - r)²
9/r² = 1/(16 - r)²
Taking square root both sides,
3/r = 1/(16 - r)
48 - 3r = r
48 = 4r
r = 12cm
Hence, a point charge q is kept 12cm from +9e
Now, at equilibrium
Force act on q due to +9e = Force act on q due to +1e
K(+9e)q/r² = k(+1e)q/(16 - r)²
9/r² = 1/(16 - r)²
Taking square root both sides,
3/r = 1/(16 - r)
48 - 3r = r
48 = 4r
r = 12cm
Hence, a point charge q is kept 12cm from +9e
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Answer is 4cm from smaller charge
12cm from bigger charge
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