Question

Two point charges, each of +4uC are separated by a distance of 20 cm. What is the Ē at a point
at a distance of 20 cm from each of them ?​

Answer 1

Answer:

hey mate please refer to the attached image....

Answer 2

The Electrostatic force at a point at a distance of 20 cm from each of them is 3.6 Newtons.

1.  Since force is equal to K* q1*q2/distance*distance

     Where i) q1 and q2 are charges

                ii) k is the constant

                iii) distance is the radial distance at which force is to        be  calculated.

2. which will be equal to 9*10^9*4*10^-6*4*10^-6/0.2^2

3. which will be equal to 3.6 Newtons.