Question

two point charges of +3×10^-6C and-8×10^-6C attract each other with a force of 1N.a charge of 5×10^-6C is added to each of them. now, the force will be?

Answer 1

Answer:

1 N

Explanation:

$F = k \frac{q_1q_2 }{ {r}^{2} } \\ \\ F = k \frac{(3 \times {10}^{ - 6})( - 8 \times {10}^{ - 6} )}{ {r}^{2} } \\ \\ F = - k \frac{24 \times {10}^{ - 12} }{ {r}^{2} } \\ \\ given \: \: \: F = 1 \\ \\ = > - \frac{k}{ {r}^{2} } = \frac{1}{24 \times {10}^{ - 12} } \\ \\ now \\ \\ F {}^{?} = k \frac{(8 \times {10}^{ - 6} )( - 3 \times {10}^{ - 6} )}{ {r}^{2} } \\ \\ F {}^{?} = - \frac{k}{ {r}^{2} } \times 24 \times {10}^{ - 12} \\ \\ F {}^{?} = 1 \: \: newton$

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