Question

two point charges of + 3 microcoulomb and + 4 microcoulomb repel each other with a force of 10 Newton if it is given an additional charge of minus 6 microcoulomb then the new forces​

Answer 1

Answer

5 N

Explanation

Given in the question,

q1 = 3μC

q2 = 4μC

K= 9 x 10^9 Nm²C$^{-2}$

Formula to use

F = (K x q1 x q2) / r²

Plug values in the equation

10 = ( 9 x 10^9 x 3 x 10^-6 x 4 x 10^-6) / r²

r² = 0.108/10

r² = 0.0108

Step 2

add -6μC in every charge

now q1 = -3μC

       q2 = -2μC

Step 3

F = (K x q1 x q2) / r²

F = (9 x 10^9 x 3 x 10^-6 x 2 x 10^-6) / 0.0108

F = 5 N