Question

two point charges of equal magnitude 5 coulomb are at a separation of 3 metre find the net force acting on charge​

Answer 1

Answer:

Step-by-step explanation:

The distance between two charges is r=

(2−1)

2

+(3−1)

2

+(1−1)

2

​

=

5

​

By Coulomb's law, the force between two charges is F=

4πϵ

0

​

1

​

r

2

q

1

​

q

2

​

​

=(9×10

9

)(

5

3×10

−6

×3×10

−6

​

)=16.2×10

−3

N