Physics, asked by vp08122003, 10 months ago

Two point charges one 4 times as strong as the other are placed at a certain distance apart in air. The force between them is 0.4 N. When the distance between them is decreased by 10 cm, the force is increased by 0.5 N, calculate the charges and their original separation

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Answered by dia190

Explanation:

The force between them is 0.4 N. When the distance between them is decreased by 10 cm, the force is increased by 0.5 N, calculate the charges and their original measurements

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