Question

two point charges,one is 10 times as stronger as the other repel each other with a force of 3.6*10^-5N when they are in air.The magnitude of the smaller charge is .

Answer 1

Hey Dear,

◆ Answer -

q1 = 2×10^-8 C

◆ Explanation -

# Given -

q2 = 10q1

F = 3.6×10^-5 N

# Solution -

Distance between two charges is not given, so we'll assume unit distance. i.e. 1 m.

Using Coulombs law of electrostatics -

F = k.q1.q2 / r^2

3.6×10^-5 = 9×10^9 × q1 × 10q1 / 1^2

q1^2 = 3.6×10^-5 / 9×10^10

q1^1 = 4×10^-16

q1 = 2×10^-8 C

Therefore, magnitude of smaller charge is 2×10^-8 C.

Hope this helped you. Thanks for asking..