Question

Two point charges placed at a distance r in air and exert force f on each other the same force in a medium of dielectric constant k is

Answer 1

SOLUTION

$\frac{1}{4\pi∈0}. \frac{q1q2}{ {r}^{2} } = \frac{1}{4\pi∈0}. \frac{q1q2}{</u><u>K</u><u> {r}</u><u>'</u><u>^{2} } \\ \\ = > \frac{1}{ {r}^{2} } = \frac{1}{ {kr}^{2} } \\ \\ = > </u><u>r'</u><u> = \frac{r}{ \sqrt{</u><u>K</u><u>} }$

hope it helps ☺️